为什么使用此计算器
工业厂房中电机、加热与电子负载混合运行,自然功率因数低于 0.9,且谐波显著。本计算器将连接设备负荷转化为选型后的变压器与开关柜方案,并按 GB 50052 与 GB 50055 进行无功补偿与谐波滤波。
Worked Examples
Example 1 — 2 MW Factory Load (Demand Factor, Motor & Harmonic Share) · FOB $257,923
| Equipment | Model | Spec | Qty |
|---|---|---|---|
| HV incoming panel | KYN28A-12-630-315 | 630 A / 31.5 kA · vacuum | 1 |
| Main transformer | S13-M-1600/10 | 1600 kVA · Oil-Immersed · Copper · S13 | 1 |
| LV incoming panel | GGD-2500 | 2500 A busbar · In 2309 A | 1 |
| LV feeder panel (×2) | GGD-2500 | distributes 8 circuits | 2 |
| Cable branch box (LV) | DFW-0.4 | 1-in / 4-out · 0.4 kV · 630 A | 1 |
| Main feeder cable (TX→LV) | YJV 0.6/1kV 300 mm² ×5 | 5× 300 mm² Cu · ΔU 1.20% @ 80 m · $154.0/m | 5 |
| Feeder cable — Plant feeder 1 (×8) | YJV 300 mm² | 300 mm² Cu · 440 A · ΔU 1.1% · $154.0/m | 8 |
| Branch trunk cable (LV → branch box 1) | YJV 300 mm² ×4 | 4× 300 mm² Cu · 1760 A · ΔU 1.1% · $154.0/m | 4 |
| Main busbar (Cu) | Cu 125×10 | 125×10 · 2500 A rating · ref $147.8/m | included |
| Grounding electrode | Φ20mm × 2.5m rod | R₁ 39.6 Ω → 13 rod(s) ≤ 4 Ω | 13 |
| Detuned PFC capacitor bank | 443 kvar | automatic · 7% detuned · 0.4 kV | 1 |
| Series detuning reactor (7%) | 31.0 kvar | 189 Hz tuning · below 5th harmonic | 1 |
| Circuit | Protection | Setting | Time | Standard |
|---|---|---|---|---|
| HV incoming 10 kV | 50 instantaneous | 739 A | inst | IEC 60255-151 / IEEE 242 |
| HV incoming 10 kV | 51 overcurrent | 111 A | 0.5 s | IEC 60255-151 / IEEE 242 |
| HV incoming 10 kV | 51N earth-fault | 18 A | 0.5 s | IEC 60364-4-41 |
| Transformer 1600 kVA | 49 thermal overload | 79% of rated | alarm 90% | IEC 60076-7 / IEEE C57.91 |
| LV incoming 0.4 kV | 50 instantaneous | 18475 A | inst | IEC 60947-2 |
| LV incoming 0.4 kV | 51 overcurrent | 2771 A | 0.3 s | IEC 60947-2 / IEC 60255 |
| LV incoming 0.4 kV | 51N earth-fault | 462 A | 0.3 s | IEC 60364-4-41 |
| Plant feeder 1 | 50/51/51N (MCCB) | Ir 484 A - Im 3520 A - Ig 88 A | 0.1 s (grading) | IEC 60947-2 / IEC 60255 |
| Plant feeder 2 | 50/51/51N (MCCB) | Ir 484 A - Im 3520 A - Ig 88 A | 0.1 s (grading) | IEC 60947-2 / IEC 60255 |
| Plant feeder 3 | 50/51/51N (MCCB) | Ir 484 A - Im 3520 A - Ig 88 A | 0.1 s (grading) | IEC 60947-2 / IEC 60255 |
| Plant feeder 4 | 50/51/51N (MCCB) | Ir 484 A - Im 3520 A - Ig 88 A | 0.1 s (grading) | IEC 60947-2 / IEC 60255 |
| Plant feeder 5 | 50/51/51N (MCCB) | Ir 484 A - Im 3520 A - Ig 88 A | 0.1 s (grading) | IEC 60947-2 / IEC 60255 |
| Plant feeder 6 | 50/51/51N (MCCB) | Ir 484 A - Im 3520 A - Ig 88 A | 0.1 s (grading) | IEC 60947-2 / IEC 60255 |
| +2 more feeders | 50/51/51N (MCCB) | per feeder load | 0.1 s (grading) | IEC 60947-2 |
| Parameter | Formula | Value |
|---|---|---|
| Connected load | P = sum(kW) | 2,000 kW |
| Demand factor | Kd | 0.6 |
| Demand power | Pd = P x Kd | 1,200 kW |
| Power factor | cos(phi) before -> after | 0.82 -> 0.95 |
| Design apparent power | Sd = Pd / cos(phi) | 1,263 kVA |
| Transformer loading | Sd / Srated | 79% |
| Parameter | Formula | Value |
|---|---|---|
| System impedance (pu) | Zs = S / Ssc | 0.32% (on 1600 kVA base) |
| Transformer impedance | Zt = Z% | 4% |
| Total impedance | Z = Zt + Zs | 4.32% |
| LV prospective Isc | Isc = In / Z | 53.5 kA |
| HV prospective Isc | Isc = Ssc / (sqrt(3) x V) | 28.9 kA |
| Breaking check | Icu >= Isc | LV 65 kA (1.2x margin) PASS |
| Parameter | Formula | Value |
|---|---|---|
| Main feeder | dU = sqrt(3) x I x L x R / V | 300 mm2 - dU 1.20% @ 80 m |
| Limit | max 3% | within limit |
| Transformer volt. reg. | dU ~ loading x Z% x sin(phi) | 1.0% at full load |
| Parameter | Formula | Value |
|---|---|---|
| Required compensation | Qc = Pd x (tan1 - tan2) | 0 kvar |
| PFC bank | standard step | 0 kvar |
| Detuned reactor | p = 6% | n/a |
| Parameter | Formula | Value |
|---|---|---|
| Single rod resistance | R1 = rho/(2 x pi x L) x ln(4L/d) | 39.6 ohm |
| Rods required | n = R1 / (target x 0.8) | 13 rod(s) <= 4 ohm |
| Rod spec | dia x length | 20 mm x 2.5 m |
| Parameter | Value |
|---|---|
| Connected load | 2,000 kW |
| Demand factor | 0.6 → demand 1,200 kW |
| Motor share | 60% (720 kW) |
| Harmonic-source share | 25% (300 kW) |
| Parameter | Value |
|---|---|
| Reactive compensation | 443 kvar detuned bank (7% reactor) |
| Harmonic current | Ih 137 A @ 30% THDi |
| APF required | No — below 30% threshold |
| Topic | Standard |
|---|---|
| Standard basis | IEC · IEC 60364-5-52 |
| Conductor ampacity | IEC 60364-5-52 Table B.52.2–B.52.5 (copper, 3 loaded conductors, 30°C ambient, PVC) — typical/rounded values, conservative (±3%) |
| Voltage-drop limit | IEC 60364-5-52 Annex G · max drop 3% |
| Winding temp rise | IEC 60076-2 — winding temp rise 65 K (Class A insulation, ONAN) |
| kVA ratings | IEC 60076-1 R10 preferred numbers |
| Breaker frames | IEC 60947-2 frame sizes (In) |
| Grounding target | IEC 60364-5-54 earthing arrangements and protective conductors — LV earthing target ≤ 10 Ω (TN systems); 4 Ω used as a conservative design target · target 4 Ω |
| Power supply design | GB 50052 — code for design of electric power supply systems |
| Low-voltage distribution | GB 50055 — code for design of electric equipment for industrial facilities |
| Harmonics | GB/T 14549 — quality of electric energy supply: harmonics in public supply network |
| Transformers | IEC 60076 — power transformers |
| Summary | |||||
|---|---|---|---|---|---|
| Estimated total (FOB Qingdao, EXW) — priced equipment | $257,923 | ||||
计算过程说明
选型计算原理
计算功率 P = 连接负荷 × 需用系数 Kd(并非所有设备同时运行)。电机占比决定自然功率因数;无功补偿 Qc = P × (tanφ₁ − tanφ₂) 将其校正至目标 PF。谐波源占比给出谐波电流 Ih = I₁ × THDi,由调谐电容器组滤波。
适用标准
选型参考 GB 50052(供配电设计)、GB 50055(工业低压配电设计)、GB/T 14549(谐波)及 IEC 60076(变压器)。
常见问题
工业园区该取多大的需用系数?
园区多家工厂不会同时开满设备,需用系数典型 0.55-0.7。2000 kW 装机、0.6 需用系数、0.9 功率因数得约 1330 kVA,宜配 1600 kVA 或两台 800 kVA。计算器用需用系数与电机占比为中低压厂区选型。
工厂密集的园区需要多少谐波治理?
当 60% 负荷为变频电机、25% 为非线性(整流、UPS)时,THDi 可达 15-25%。IEEE 519 要求公共连接点 THD 限 5-8%,故需 7% 去谐电容器组或 APF。计算器按谐波占比配置补偿与去谐。
工业园区的标准中低压架构是怎样的?
典型架构:10 kV(或 35 kV)市电 → 环网或放射式中压开关柜 → 每厂/每区块一台变压器 → 0.4 kV 开关柜 → 电机控制中心。沿环网布置环网柜的 10 kV 环网可提供 N-1 供电。计算器为园区聚合负荷选变压器、开关柜与补偿。
如何为每家工厂分配变压器容量?
每家工厂配一台按需用容量加 20-25% 裕量的独立变压器,小租户可合用一台大变压器。独立变压器隔离故障、便于计量,但共享方案成本更低。计算器聚合园区需量并给出单台与分拆方案。
工业园区应维持多大功率因数?
供电公司通常要求 0.9-0.95 功率因数,低于约 0.9 收取罚金。电机为主的园区初始功率因数 0.75-0.85,加电容器组可提到 0.95。计算器算出从实测 pf 到目标所需的 kvar 补偿并选低压电容柜。
园区中压网络通常提供什么冗余?
带常开联络的环网中压网络提供 N-1 冗余:任一段电缆或环网柜故障可被隔离并从另一方向恢复供电。放射式馈线更便宜但故障即失电。计算器的架构说明覆盖环网与放射式的可靠性和成本权衡。
嵌入此计算器
复制下方 iframe 代码,即可将此计算器嵌入任何网站。嵌入页面为 noindex,适配任意宽度。
相关计算器
结果为工程估算,仅供参考。最终设计须由当地持证工程师根据现场条件和适用规范确认。价格为青岛交货价 FOB(EXW),不含运费、关税及安装费。
发送我的完整设计报告
免费获取完整设备清单(BOM)、单线图、计算步骤与 FOB 报价的 PDF 报告,无需注册。
您的信息仅用于回复询盘,不用于任何其他用途。