Transformador QDTB®

Calculadora de Harmónicos e Filtro Desafinado (PFC)

Dimensionar uma bateria de condensadores de correção do fator de potência com um reator de desafinação em série — kvar de compensação, verificação da frequência de ressonância e a configuração do filtro.

Começar a Calcular

Resultado

Insira sua carga → obtenha um projeto completo e BOM em segundos

Saída de exemplo
Required compensation
277 kvar
400 kW · PF 0.7 → 0.95 · THDi 30% · 7% reactor
Fundamental current
825 A
Harmonic current
247 A
Resonance freq
189 Hz
Cap voltage
430 V
Calculation
QuantityValue
Reactive power QcP × (tanφ₁ − tanφ₂) = 400 × (1.020 − 0.329) = 276.6 kvar
Fundamental current I₁P ÷ (√3·V·PF) = 400 kW ÷ (√3 × 400 V × 0.7) = 824.8 A
Harmonic current IhI₁ × THDi = 824.8 × 30% = 247.4 A
LC resonance frequencyf₁ ÷ √(p) = 50 ÷ √(0.070) = 189 Hz
Dominant harmonic5ᵗʰ = 250 Hz → above resonance (filter is inductive) — Detuned — safe from resonance ✓
Capacitor voltageV ÷ (1 − p) = 400 ÷ 0.93 = 430 V
Reactor rating7% × 277 = 19.4 kvar
Filter configuration
277 kvar capacitor bank + 7% detuning reactor (19.4 kvar)
Detuned at 189 Hz, below the 5ᵗʰ harmonic (250 Hz) — the branch stays inductive at the dominant harmonic, preventing resonance amplification.
Bill of materials
EquipmentSpecQtySubtotal
Power factor correction capacitor bank277 kvar · 400 V · detuned1POA
Series detuning reactor (7%)19.4 kvar · 189 Hz tuning1POA
Total equipmentPOA

Para engenheiros que projetam correção do fator de potência e filtros de harmónicos desafinados em redes com variadores de velocidade e outras cargas não lineares.

Utilizar a calculadora

Exemplo prático

Um exemplo de referência pré-calculado (rastreável — não requer JavaScript). Introduza os seus próprios parâmetros acima para um resultado em tempo real.

Exemplo resolvido — 400 kW, PF 0,70→0,95, THDi 30%, reator de 7%

Required compensation
277 kvar
400 kW · PF 0.7 → 0.95 · THDi 30% · 7% reactor
Fundamental current
825 A
Harmonic current
247 A
Resonance freq
189 Hz
Cap voltage
430 V
Calculation
QuantityValue
Reactive power QcP × (tanφ₁ − tanφ₂) = 400 × (1.020 − 0.329) = 276.6 kvar
Fundamental current I₁P ÷ (√3·V·PF) = 400 kW ÷ (√3 × 400 V × 0.7) = 824.8 A
Harmonic current IhI₁ × THDi = 824.8 × 30% = 247.4 A
LC resonance frequencyf₁ ÷ √(p) = 50 ÷ √(0.070) = 189 Hz
Dominant harmonic5ᵗʰ = 250 Hz → above resonance (filter is inductive) — Detuned — safe from resonance ✓
Capacitor voltageV ÷ (1 − p) = 400 ÷ 0.93 = 430 V
Reactor rating7% × 277 = 19.4 kvar
Filter configuration
277 kvar capacitor bank + 7% detuning reactor (19.4 kvar)
Detuned at 189 Hz, below the 5ᵗʰ harmonic (250 Hz) — the branch stays inductive at the dominant harmonic, preventing resonance amplification.
Bill of materials
EquipmentSpecQtySubtotal
Power factor correction capacitor bank277 kvar · 400 V · detuned1POA
Series detuning reactor (7%)19.4 kvar · 189 Hz tuning1POA
Total equipmentPOA

Exemplo resolvido — 800 kW, PF 0,75→0,98, THDi 25%, reator de 6%

Required compensation
543 kvar
800 kW · PF 0.75 → 0.98 · THDi 25% · 6% reactor
Fundamental current
1540 A
Harmonic current
385 A
Resonance freq
204 Hz
Cap voltage
426 V
Calculation
QuantityValue
Reactive power QcP × (tanφ₁ − tanφ₂) = 800 × (0.882 − 0.203) = 543.1 kvar
Fundamental current I₁P ÷ (√3·V·PF) = 800 kW ÷ (√3 × 400 V × 0.75) = 1539.6 A
Harmonic current IhI₁ × THDi = 1539.6 × 25% = 384.9 A
LC resonance frequencyf₁ ÷ √(p) = 50 ÷ √(0.060) = 204 Hz
Dominant harmonic7ᵗʰ = 350 Hz → above resonance (filter is inductive) — Detuned — safe from resonance ✓
Capacitor voltageV ÷ (1 − p) = 400 ÷ 0.94 = 426 V
Reactor rating6% × 543 = 32.6 kvar
Filter configuration
543 kvar capacitor bank + 6% detuning reactor (32.6 kvar)
Detuned at 204 Hz, below the 7ᵗʰ harmonic (350 Hz) — the branch stays inductive at the dominant harmonic, preventing resonance amplification.
Bill of materials
EquipmentSpecQtySubtotal
Power factor correction capacitor bank543 kvar · 400 V · detuned1POA
Series detuning reactor (6%)32.6 kvar · 204 Hz tuning1POA
Total equipmentPOA

Como foi calculado

  • · Potência reativa: Qc = P × (tanφ₁ − tanφ₂).
  • · Corrente harmónica: Ih = I₁ × THDi%.
  • · Frequência de ressonância LC: f_res = f₁ ÷ √(p), onde p é o fator de desafinação (6% → ≈204 Hz, 7% → ≈189 Hz, 12.5% → ≈141 Hz).
  • · Verificação de desafinação: o ramal é indutivo (sem amplificação) quando o harmónico dominante está acima de f_res.
  • · Tensão do condensador com reator: Vc = V ÷ (1 − p).

Normas referenciadas

StandardScope
GB/T 14549Qualidade do fornecimento de energia elétrica — harmónicos na rede pública de abastecimento
IEC 61000-3-2Limites para emissões de corrente harmónica (equipamentos ≤ 16 A)
IEC 61642Redes industriais de corrente alternada afetadas por harmónicos
IEEE 519Prática recomendada para o controlo de harmónicos em sistemas de energia elétrica

Perguntas frequentes

What harmonic limits does IEEE 519 impose?

IEEE 519 limits total demand distortion (TDD) at the point of common coupling, typically 5% for systems below 69 kV, with individual harmonic limits (e.g. 5th/7th capped around 4%). Stricter limits apply where the short-circuit ratio is low. The calculator sizes filtering to meet these limits.

What is the difference between a passive and active harmonic filter?

A passive filter is a tuned LC circuit (often a detuned capacitor bank) that traps a specific harmonic; cheap but fixed. An active harmonic filter (APF) injects a cancelling current dynamically, handling multiple and varying Harmonics at 2-4x the cost. The calculator recommends detuned banks for steady harmonics and APF for dynamic loads.

Why do VFDs cause harmonics?

VFD rectifiers draw current in pulses rather than a sine wave, generating 5th, 7th, 11th and 13th harmonics (6-pulse drives). A 6-pulse VFD can produce 30-40% THDi at the drive terminals; 12- or 18-pulse and active-front-end drives reduce it. The calculator models the harmonic source share.

What detuning factor protects a capacitor bank from resonance?

A 7% series Reactor detunes the capacitor bank below the 5th harmonic so the bank never resonates with the network at 250 Hz. A 6% reactor is used when only the 5th harmonic is significant; 7% is the default for networks with 5th and higher harmonics. The calculator applies the detuning factor.

How do I estimate the harmonic filter kVAR needed?

The filter kVAR is based on the non-linear load share and the required distortion reduction. As a rule of thumb, size detuned capacitors to 25-35% of the VFD load, and an APF to 15-25% of the harmonic-producing load. The calculator estimates the compensation and filter rating from the load mix.

Incorporar esta calculadora

Adicione esta calculadora ao seu próprio site gratuitamente. O iframe adapta-se a qualquer largura e é executado inteiramente no navegador do seu visitante.

Ferramentas relacionadas

Estimativas de referência (FOB Qingdao, EXW) apenas para projeto preliminar — não é um orçamento final. Confirme o dimensionamento com o seu projeto e as normas locais.

Send my complete design report

Get the full bill of materials, single-line diagram, calculation steps and FOB pricing as a PDF — free, no sign-up.

💬 Chat on WhatsApp

Your data stays private. No spam — only a reply to your enquiry.