Kalkulator Harmonisa & Filter Detuned (PFC)
Ukuran bank kapasitor koreksi faktor daya dengan reaktor detuning seri — kompensasi kvar, pemeriksaan frekuensi resonansi, dan konfigurasi filter.
Hasil
Masukkan beban Anda → dapatkan desain lengkap & BOM dalam hitungan detik
Contoh keluaran| Quantity | Value |
|---|---|
| Reactive power Qc | P × (tanφ₁ − tanφ₂) = 400 × (1.020 − 0.329) = 276.6 kvar |
| Fundamental current I₁ | P ÷ (√3·V·PF) = 400 kW ÷ (√3 × 400 V × 0.7) = 824.8 A |
| Harmonic current Ih | I₁ × THDi = 824.8 × 30% = 247.4 A |
| LC resonance frequency | f₁ ÷ √(p) = 50 ÷ √(0.070) = 189 Hz |
| Dominant harmonic | 5ᵗʰ = 250 Hz → above resonance (filter is inductive) — Detuned — safe from resonance ✓ |
| Capacitor voltage | V ÷ (1 − p) = 400 ÷ 0.93 = 430 V |
| Reactor rating | 7% × 277 = 19.4 kvar |
| Equipment | Spec | Qty | Subtotal |
|---|---|---|---|
| Power factor correction capacitor bank | 277 kvar · 400 V · detuned | 1 | POA |
| Series detuning reactor (7%) | 19.4 kvar · 189 Hz tuning | 1 | POA |
| Total equipment | POA |
Untuk insinyur yang merancang koreksi faktor daya dan filter harmonisa detuned pada jaringan dengan variable-speed drive dan beban non-linear lainnya.
Gunakan kalkulator
Contoh perhitungan
Contoh referensi yang telah dihitung sebelumnya (dapat dirayapi — tidak memerlukan JavaScript). Masukkan parameter Anda sendiri di atas untuk hasil langsung.
Contoh perhitungan — 400 kW, PF 0.70→0.95, THDi 30%, reaktor 7%
| Quantity | Value |
|---|---|
| Reactive power Qc | P × (tanφ₁ − tanφ₂) = 400 × (1.020 − 0.329) = 276.6 kvar |
| Fundamental current I₁ | P ÷ (√3·V·PF) = 400 kW ÷ (√3 × 400 V × 0.7) = 824.8 A |
| Harmonic current Ih | I₁ × THDi = 824.8 × 30% = 247.4 A |
| LC resonance frequency | f₁ ÷ √(p) = 50 ÷ √(0.070) = 189 Hz |
| Dominant harmonic | 5ᵗʰ = 250 Hz → above resonance (filter is inductive) — Detuned — safe from resonance ✓ |
| Capacitor voltage | V ÷ (1 − p) = 400 ÷ 0.93 = 430 V |
| Reactor rating | 7% × 277 = 19.4 kvar |
| Equipment | Spec | Qty | Subtotal |
|---|---|---|---|
| Power factor correction capacitor bank | 277 kvar · 400 V · detuned | 1 | POA |
| Series detuning reactor (7%) | 19.4 kvar · 189 Hz tuning | 1 | POA |
| Total equipment | POA |
Contoh perhitungan — 800 kW, PF 0.75→0.98, THDi 25%, reaktor 6%
| Quantity | Value |
|---|---|
| Reactive power Qc | P × (tanφ₁ − tanφ₂) = 800 × (0.882 − 0.203) = 543.1 kvar |
| Fundamental current I₁ | P ÷ (√3·V·PF) = 800 kW ÷ (√3 × 400 V × 0.75) = 1539.6 A |
| Harmonic current Ih | I₁ × THDi = 1539.6 × 25% = 384.9 A |
| LC resonance frequency | f₁ ÷ √(p) = 50 ÷ √(0.060) = 204 Hz |
| Dominant harmonic | 7ᵗʰ = 350 Hz → above resonance (filter is inductive) — Detuned — safe from resonance ✓ |
| Capacitor voltage | V ÷ (1 − p) = 400 ÷ 0.94 = 426 V |
| Reactor rating | 6% × 543 = 32.6 kvar |
| Equipment | Spec | Qty | Subtotal |
|---|---|---|---|
| Power factor correction capacitor bank | 543 kvar · 400 V · detuned | 1 | POA |
| Series detuning reactor (6%) | 32.6 kvar · 204 Hz tuning | 1 | POA |
| Total equipment | POA |
Cara perhitungannya
- · Daya reaktif: Qc = P × (tanφ₁ − tanφ₂).
- · Arus harmonisa: Ih = I₁ × THDi%.
- · Frekuensi resonansi LC: f_res = f₁ ÷ √(p), di mana p adalah faktor detuning (6% → ≈204 Hz, 7% → ≈189 Hz, 12.5% → ≈141 Hz).
- · Pemeriksaan detuning: cabang bersifat induktif (tanpa amplifikasi) ketika harmonisa dominan berada di atas f_res.
- · Tegangan kapasitor dengan reaktor: Vc = V ÷ (1 − p).
Standar yang dirujuk
| Standard | Scope |
|---|---|
| GB/T 14549 | Kualitas pasokan energi listrik — harmonisa pada jaringan suplai publik |
| IEC 61000-3-2 | Batas emisi arus harmonisa (peralatan ≤ 16 A) |
| IEC 61642 | Jaringan a.c. industri yang terpengaruh harmonisa |
| IEEE 519 | Praktik yang direkomendasikan untuk pengendalian harmonisa pada sistem tenaga listrik |
Pertanyaan yang sering diajukan
What harmonic limits does IEEE 519 impose?
IEEE 519 limits total demand distortion (TDD) at the point of common coupling, typically 5% for systems below 69 kV, with individual harmonic limits (e.g. 5th/7th capped around 4%). Stricter limits apply where the short-circuit ratio is low. The calculator sizes filtering to meet these limits.
What is the difference between a passive and active harmonic filter?
A passive filter is a tuned LC circuit (often a detuned capacitor bank) that traps a specific harmonic; cheap but fixed. An active harmonic filter (APF) injects a cancelling current dynamically, handling multiple and varying Harmonics at 2-4x the cost. The calculator recommends detuned banks for steady harmonics and APF for dynamic loads.
Why do VFDs cause harmonics?
VFD rectifiers draw current in pulses rather than a sine wave, generating 5th, 7th, 11th and 13th harmonics (6-pulse drives). A 6-pulse VFD can produce 30-40% THDi at the drive terminals; 12- or 18-pulse and active-front-end drives reduce it. The calculator models the harmonic source share.
What detuning factor protects a capacitor bank from resonance?
A 7% series Reactor detunes the capacitor bank below the 5th harmonic so the bank never resonates with the network at 250 Hz. A 6% reactor is used when only the 5th harmonic is significant; 7% is the default for networks with 5th and higher harmonics. The calculator applies the detuning factor.
How do I estimate the harmonic filter kVAR needed?
The filter kVAR is based on the non-linear load share and the required distortion reduction. As a rule of thumb, size detuned capacitors to 25-35% of the VFD load, and an APF to 15-25% of the harmonic-producing load. The calculator estimates the compensation and filter rating from the load mix.
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