Transformator QDTB®

Kalkulator Operasi Paralel Transformator

Verifikasi apakah dua transformator dapat beroperasi paralel (kelompok vektor, rasio, impedansi, rasio kapasitas) dan lihat bagaimana beban terbagi di antara keduanya dalam proporsi terbalik terhadap impedansi hubung singkatnya.

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Hasil

Masukkan beban Anda → dapatkan desain lengkap & BOM dalam hitungan detik

Contoh keluaran
Parallel load sharing
798 / 502 kVA
1300 kVA total across 1000 kVA (uk 6%) + 630 kVA (uk 6%) · Feasible for parallel operation ✓
Transformer A loading
80%
Transformer B loading
80%
Combined capacity
1630 kVA
Overall load factor
80%
Parallel-operation conditions (IEC 60076)
ConditionValueVerdict
Same vector groupMatched (e.g. Dyn11 = Dyn11)PASS ✓
Same voltage ratio0% difference (≤ 0.5% recommended)PASS ✓
Impedance within tolerance|uk_A − uk_B| = 0.0% of mean (≤ 10%)PASS ✓
Capacity ratio ≤ 3:11.59 : 1PASS ✓
Load sharing calculation
Weight ASa ÷ uk_A = 1000 ÷ 6 = 166.7
Weight BSb ÷ uk_B = 630 ÷ 6 = 105.0
Load A1300 × 166.7 ÷ 271.7 = 798 kVA (80%)
Load B1300 × 105.0 ÷ 271.7 = 502 kVA (80%)
Conclusion
The two units can operate in parallel; load splits in inverse proportion to their short-circuit impedance.
Bill of materials
EquipmentSpecQtySubtotal
Transformer A (oil-immersed S11)1000 kVA · uk 6%1POA
Transformer B (oil-immersed S11)630 kVA · uk 6%1POA
Total equipmentPOA

Untuk insinyur sistem tenaga dan pabrik yang menghitung ukuran bank transformator paralel untuk redundansi, ekspansi kapasitas, atau keandalan N−1.

Gunakan kalkulator

Contoh perhitungan

Contoh referensi yang telah dihitung sebelumnya (dapat dirayapi — tidak memerlukan JavaScript). Masukkan parameter Anda sendiri di atas untuk hasil langsung.

Contoh 1 — 1000 kVA + 630 kVA, impedansi 6% yang cocok

Parallel load sharing
798 / 502 kVA
1300 kVA total across 1000 kVA (uk 6%) + 630 kVA (uk 6%) · Feasible for parallel operation ✓
Transformer A loading
80%
Transformer B loading
80%
Combined capacity
1630 kVA
Overall load factor
80%
Parallel-operation conditions (IEC 60076)
ConditionValueVerdict
Same vector groupMatched (e.g. Dyn11 = Dyn11)PASS ✓
Same voltage ratio0% difference (≤ 0.5% recommended)PASS ✓
Impedance within tolerance|uk_A − uk_B| = 0.0% of mean (≤ 10%)PASS ✓
Capacity ratio ≤ 3:11.59 : 1PASS ✓
Load sharing calculation
Weight ASa ÷ uk_A = 1000 ÷ 6 = 166.7
Weight BSb ÷ uk_B = 630 ÷ 6 = 105.0
Load A1300 × 166.7 ÷ 271.7 = 798 kVA (80%)
Load B1300 × 105.0 ÷ 271.7 = 502 kVA (80%)
Conclusion
The two units can operate in parallel; load splits in inverse proportion to their short-circuit impedance.
Bill of materials
EquipmentSpecQtySubtotal
Transformer A (oil-immersed S11)1000 kVA · uk 6%1POA
Transformer B (oil-immersed S11)630 kVA · uk 6%1POA
Total equipmentPOA

Contoh 2 — impedansi dan rasio yang tidak cocok

Parallel load sharing
883 / 417 kVA
1300 kVA total across 1000 kVA (uk 6%) + 630 kVA (uk 8%) · Not recommended — check conditions below ✗
Transformer A loading
88%
Transformer B loading
66%
Combined capacity
1630 kVA
Overall load factor
80%
Parallel-operation conditions (IEC 60076)
ConditionValueVerdict
Same vector groupMatched (e.g. Dyn11 = Dyn11)PASS ✓
Same voltage ratio1.5% difference (≤ 0.5% recommended)FAIL ✗
Impedance within tolerance|uk_A − uk_B| = 28.6% of mean (≤ 10%)FAIL ✗
Capacity ratio ≤ 3:11.59 : 1PASS ✓
Load sharing calculation
Weight ASa ÷ uk_A = 1000 ÷ 6 = 166.7
Weight BSb ÷ uk_B = 630 ÷ 8 = 78.8
Load A1300 × 166.7 ÷ 245.4 = 883 kVA (88%)
Load B1300 × 78.8 ÷ 245.4 = 417 kVA (66%)
Circulating current
A 1.5% no-load ratio difference drives a circulating current of ≈ 80 kVA between the two units (adds to the load, does not supply the load).
Bill of materials
EquipmentSpecQtySubtotal
Transformer A (oil-immersed S11)1000 kVA · uk 6%1POA
Transformer B (oil-immersed S11)630 kVA · uk 8%1POA
Total equipmentPOA

Cara perhitungannya

  • · Bobot pembagian beban: w = S_nom ÷ uk untuk setiap unit.
  • · Beban unit A: S_A = S × w_A ÷ (w_A + w_B); unit B juga demikian.
  • · Pembebanan: S_A ÷ S_nom,A (harus tetap ≤ 100%).
  • · Kondisi paralel: kelompok vektor sama, rasio tegangan sama (≤0,5%), impedansi dalam ±10% satu sama lain, rasio kapasitas ≤ 3:1.
  • · Arus sirkulasi (ketidaksesuaian rasio): I_c ≈ ΔU ÷ (Z_A + Z_B) dalam per-unit.

Standar yang dirujuk

StandardScope
IEC 60076-1Transformator daya — persyaratan umum
IEC 60076-8Transformator daya — panduan aplikasi
IEEE C57.12.00Standar persyaratan umum untuk transformator distribusi dan daya terendam cairan

Pertanyaan yang sering diajukan

What conditions must transformers meet to run in parallel?

Per IEC 60076, parallel transformers must match: voltage ratio (within ~0.5%), Vector Group, impedance voltage uk (within ~10%), and preferably power rating ratio under 3:1. Mismatched vector groups cause circulating current and severe overheating. The calculator checks these conditions and reports pass/fail.

How is load shared between parallel transformers?

Load shares inversely with impedance: the Transformer with lower uk carries more load. Two transformers of equal rating with uk 6% and 4.5% split load in the ratio 4.5:6, so the 4.5% unit carries 57%. The calculator computes the load share by impedance and flags overloading.

Why run transformers in parallel?

Parallel operation provides redundancy (one can be taken out for maintenance without outage), allows capacity to be added incrementally, and can improve efficiency at light load by running only one unit. The trade-off is higher fault level at the bus. The calculator models the parallel arrangement and its Fault Current.

What is circulating current between parallel transformers?

Circulating current flows when parallel transformers have unequal voltage ratios or different vector groups, even with no load, causing extra losses and heating. A 1% ratio mismatch can drive 5-10% circulating current. IEC 60076 limits the ratio difference to ~0.5%. The calculator checks for this.

What fault level results from paralleling transformers?

Paralleling transformers roughly sums their short-circuit contributions. Two 1000 kVA, 6% uk transformers give ~48 kA at the LV bus versus ~24 kA for one, so the switchgear must be uprated. The calculator computes the combined fault level so you can check panel ratings.

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